Milke

t = (X*H^.1.33)/release rate^(.33)

X=4.6*10^-4*Y^2+2.7*10^-15*Y^6
where Y = DeltaT(given)*H^5/3/release rate^2/3

(Hey, you firefighters donna messaroun', you know dat?)

• The Heat Release Rate 250 BTU/s.
• The inside temperature is 75 degrees F
• The detector alarm temperature is 135 degrees F.
• The ceiling height in the living room is 10 ft
• The heat detector is located on the living room ceiling, approximately 2 ft. from the centerline of the fire.
• The Response Time Index (RTI) of the heat detector is 100.
• The fire can be assumed to be Steady State.

Okay: I think the release rate conversion: 1 BTU/second equals 1.0542 kilowatt; 250 BTUs = 264kw

Required temp rise = 135 - 75 = 60 degrees

Y = 60*10ft^(5/3)/264kw^(2/3) = 67.7

X=4.6*10^-4*Y^2+2.7*10^-15*Y^6

X= 2.1

t = (X*H^.1.33)/release rate^(.33)

t = ~7 seconds

*whew*

"Math is Hard"; "Let's go shopping!"

If'n y'all believe my calcs, I'd like ta think the first guy to verify and cut/paste would be a lucky feller!