but, were you wearing sneakers or boots? If you had your boots on, a 3 story one would have done...so I'm told![]()
Well, hell George, throw the young 'uns a bone and give them the real skinny on stick rotation indicators, methods, and equipment. I'm sure you can see from the posts in this thread it is sorely needed.
I would pass it on, but everyone knows I'm not as generous as you are, and besides, I use the ggiesefoolproofevenhumiditymethod and the patent hasn't expired yet. I don't need you suing me. Again.
geesh i'm bored
one questions on the rotating.
Does the rotational force smooth out the edges on the box pressed sticks?
All this talk of rotation is making me sick.
My wife mentioned something to me the other day about "rotating sticks". I wonder if this is what she meant by it....hmmmm![]()
Rock tumbler. I just spit in it every once and a while to keep everything moist.
Ooohh... I dunno Kris. A popular misconception.
I know it's rhetorical, but formally the angular momentum of a point object is defined as the cross product of the object's position vector (a measure of an object's resistance to changes in its rotation rate) and the linear momentum vector. By that definition, angular momentum cannot possibly be the same as linear momentum.
Holy shit, you guys are making my head hurt![]()
Oh, now THIS will make your head really thump.
Ah yes, I can see that. However there will be both a slowing of momentum from friction and curvature of the linear path due to gravity.
For example, a projectile (arrows, bullets, artillery shells, etc.) will eventually slow down from atmospheric friction which allows gravity to alter the projectiles course. This arguement can also be used for light, since light waves can be altered by gravity (red shift) and be effected by interstellar dust or other celestial bodies that the light would have to pass through.
Ahh... The ol' "throwing a projectile" argument. Clever...
Isn't the linear trajectory vector of the object not expressed in two directions? One force vector represented by the forward trajectory of the object, as well as the gravity force vector acting on the object's forward path? m x a = foward trajectory, m x a = force due to gravity ...each separate and distnct, and both linear vectors? ...at least that is conventional thinking.
Or - are they both truly linear vectors? After all - where does gravity come from? So could the vector representing the force due to gravity actually be a representation of an angular force (i.e. tangential acceleration) - typically expressed as a constant value (9.8 m/sec/sec) even though it's truly not constant.
In Quantum Mechanics (which is where the scientific community studies gravitational forces) states through the Heisenberg uncertainty principle that it is not possible for the six term, 2-form Noether charge to be measured simultaneously with arbitrary precision. Therefore, there are limits to what can be known or measured about a particle's angular momentum. It turns out that the best that one can do is to simultaneously measure both the angular momentum vector's magnitude and its component along one axis.
So - I think you'll agree - it is is capricious to think that an angular component becomes linear.![]()
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