Here's a "simpler" equation:
t = (X*H^.1.33)/release rate^(.33)
Unfortunately, X is something fairly complex...
That said (and I'll likely do the math for someone's benefit), it looks like the response time is under 1 second...
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Here's a "simpler" equation:
t = (X*H^.1.33)/release rate^(.33)
Unfortunately, X is something fairly complex...
That said (and I'll likely do the math for someone's benefit), it looks like the response time is under 1 second...
50-4 = 46 post deficiet to compete in contest.
Quote:
Originally Posted by dajones
Milke
t = (X*H^.1.33)/release rate^(.33)
X=4.6*10^-4*Y^2+2.7*10^-15*Y^6
where Y = DeltaT(given)*H^5/3/release rate^2/3
(Hey, you firefighters donna messaroun', you know dat?)
• The Heat Release Rate 250 BTU/s.
• The inside temperature is 75 degrees F
• The detector alarm temperature is 135 degrees F.
• The ceiling height in the living room is 10 ft
• The heat detector is located on the living room ceiling, approximately 2 ft. from the centerline of the fire.
• The Response Time Index (RTI) of the heat detector is 100.
• The fire can be assumed to be Steady State.
Okay: I think the release rate conversion: 1 BTU/second equals 1.0542 kilowatt; 250 BTUs = 264kw
Required temp rise = 135 - 75 = 60 degrees
Y = 60*10ft^(5/3)/264kw^(2/3) = 67.7
X=4.6*10^-4*Y^2+2.7*10^-15*Y^6
X= 2.1
t = (X*H^.1.33)/release rate^(.33)
t = ~7 seconds
*whew*
"Math is Hard"; "Let's go shopping!"
If'n y'all believe my calcs, I'd like ta think the first guy to verify and cut/paste would be a lucky feller!
Quote:
Originally Posted by dajones
I think it's pretty damn rude, knowing that you don't qualify, to be posting guesses and expecting someone to plagiarize the work of a troll.
Dude, seriously - what the hell are you thinking? This contest is meant to be a fun thing for the contributing members of this site. There are rules listed at the top for a reason. Your attempt to show how smart you are is not appreciated, nor is the disrespect that you have shown me and this forum.Quote:
Originally Posted by dajones
Go away.
-Buzz
A... troll? I dinna say, e.g., "Obama is the greatest President evah!" Nor even "Don't you know cigars'll KILL YA?" You know... classic trolls.Quote:
Originally Posted by bigwhiteash
As suggested by the OP: "Show your work." In other words, how, exactly, am I trolling?
Edit:
But, since the OP himself objects, I guess I'll move along.
(Oh: OP: I wazna tryin' to show how smaht *I* am, but how tuff it mus' be to pass the fireman's exam...)
Sorry to bust in on your party. Friendly site y'all got here...
Hey Buzz..
You may want to edit the contest... we need to factor in a 5,000 BTU Flaming Asshat into the equation!
Look man, right after I said to show your work (which you paid attention to) I said you had to have at least 50 posts (which you are ignoring) - that is not appreciated at all.Quote:
Originally Posted by dajones
That would be appreciated.Quote:
Originally Posted by dajones
Yeah sure, that is exactly what you were doing. :smiley24:Quote:
Originally Posted by dajones
This site is very friendly to those who contribute positively to it.Quote:
Originally Posted by dajones
-Buzz
:smiley44::smiley51::smiley51::smiley51::smiley44:Quote:
Originally Posted by dajones
You aren't being called a troll for WHAT you said, but because you came in and participated in a contest that you clearly did not qualify for. When prompted about the number of posts needed to play, you posted your guesses anyway...even when you knew you were not qualified to do so.Quote:
Originally Posted by dajones
That is why your are being considered a troll.
Now, go away!!
*YAWN*
You're not even funny. At least you're succeeding in getting the youngsters all worked up. Maybe you'll type something that makes me laugh soon, well, at least more than the BOTL and PUFF admissions did.
Just ignore the guy...
Ok lets get back on track.
This is a tuff one, but here is my guess. The heat detector alarm will never go off.
Now let me show my work,
Buzz may have some cheap ass watered down Tequila in the house but nothing that would work as a decent accelerant, and even if he did receive a bottle of 100+ proof Tequila for Christmas it didn't last threw the day.
But lets assume the ex-girlfriend provided her own Tequila and it did make a good accelerant.
Now the 150 or so Philly blunts that Buzz is going to say were top of the line montecristo's "at least to the insurance company" are in a pile burring away at 250 BTU/s and the heat detector is around 11 feet away give or take a foot.
The detector which buzz claims is set to go off at 135 degrees and the room temperature is 75 F so you would need a 60 degree or so increase in temperature 11 feet away.
allowing for the cooling effect of the room air temperature, the distance the detector is away from the fire, allowing for the accelerant to burn off and evaporation of the high quality 100+ proof tequila.
i really don't think it would go off.
Besides Buzz never replaced the batteries in the heat detector, some how the $ his wife gave him for batteries was spent obtaining the Philly blunts and cheap tequila.
:smiley36: - don't tell people about my blunts, no one will want to win!Quote:
Originally Posted by Mangyrat
By the way, I thought you may have had an spelling-error-free post here for the first time ever... but then I read it again. :smiley17:
-Buzz
Take it easy, he just got threwn off a bit.Quote:
Originally Posted by buzz
Not like he through gasoline on a fire, or anything..
I needed a good laugh :smiley36:,
The better question is how long does it take for the fire to be put out...let me take a stab at that.
-The department is 3 miles away.
-Its presumably late at night so there will be little traffic.
-The speed limit around your house is 30 mph.
-The average "out the door time" is 45 seconds.
-Fire grows 10 times in size a minute.
So the truck arrives in 2.5 minutes roughly. They hook up to the hydrant and lay attack hose in 2 minutes. They find the fire in 3 minutes (lets assume its upstairs and everyone is assumed to be out of the house by now, so searching will not be a main priority and slow you down.) The sticks take up about 2 square feet (rough guess) initially. By the time the fire is ready to be put out the fire will be about 140 square feet (once again roughly, my math skills suck.) Flowing 150 gallons per minute (pretty standard amount for a normal attack line) it would take me as nozzle man all of ten seconds to put it out. So a total time of about 7 minutes and 40 seconds to put it out.
I think the putting it out math is way more fun...and its all I know. And I know this contest is for people with 50+ posts but I felt special actually knowing about something so I felt moved to post. Congrats on passing the test, I don't know how engineering tests are but just normal firefighting state tests are absolute bitches...but thankfully I passed mine first try.
Here's my stab at it. I subtracted the temp of the room (75 F) from the temp the alarm is set to detect (135 F) which gave me a "Temperature Bridge" or "TB" of 60 degrees. I then divided the 100 RTI of the detector by the 60 degree TB which brings us to a 1.66..."ResponseTime" or "RP". I then took into account that the ex was most likely raised in a barn (she had to be if she dated you) and left the door and window open, which caused a severe draft. So I added 15% to my 1.66 RP to compensate for windchill factor and that makes the real-time RP 1.91. Now take the 250 BTU of the flame and multiply that by 1.91=477.5, and divide that by 60. This gives you your answer which is 7.958 seconds. I've included an illustration, which should clear up any questions you have about how I figured this out.
:smiley36: Nice catch, I was wondering if someone would figure out the draft issue...Quote:
Originally Posted by SirPuffsAlot
Oh, and that picture is simply amazing - you qualify even without the 50 posts just due to the illustration!
-Buzz