Contest: Cigars ablaze!

[dajones]

Fark? I guess that is a re-deployment of the old DOS attack lingo...

*sigh*

Yet another forum (I hang at BOTL and Puff) where I hafta establish some sorta bona fides before being allowed to play.

Good luck guys!

[bigwhiteash]

Fark? I guess that is a re-deployment of the old DOS attack lingo...

*sigh*

Yet another forum (I hang at BOTL and Puff) where I hafta establish some sorta bona fides before being allowed to play.

Good luck guys!

Don't like it?

The door is in the upper right corner.

[dajones]

Don't like it?

The door is in the upper right corner.

Well a big ole HOWDY to you too, pardner!

[dajones]

Here's a "simpler" equation:

t = (X*H^.1.33)/release rate^(.33)

Unfortunately, X is something fairly complex...

That said (and I'll likely do the math for someone's benefit), it looks like the response time is under 1 second...

[dajones]

Milke

t = (X*H^.1.33)/release rate^(.33)

X=4.6*10^-4*Y^2+2.7*10^-15*Y^6
where Y = DeltaT(given)*H^5/3/release rate^2/3

(Hey, you firefighters donna messaroun', you know dat?)

• The Heat Release Rate 250 BTU/s.
• The inside temperature is 75 degrees F
• The detector alarm temperature is 135 degrees F.
• The ceiling height in the living room is 10 ft
• The heat detector is located on the living room ceiling, approximately 2 ft. from the centerline of the fire.
• The Response Time Index (RTI) of the heat detector is 100.
• The fire can be assumed to be Steady State.

Okay: I think the release rate conversion: 1 BTU/second equals 1.0542 kilowatt; 250 BTUs = 264kw

Required temp rise = 135 - 75 = 60 degrees

Y = 60*10ft^(5/3)/264kw^(2/3) = 67.7

X=4.6*10^-4*Y^2+2.7*10^-15*Y^6

X= 2.1

t = (X*H^.1.33)/release rate^(.33)

t = ~7 seconds

*whew*

"Math is Hard"; "Let's go shopping!"

If'n y'all believe my calcs, I'd like ta think the first guy to verify and cut/paste would be a lucky feller!

[bigwhiteash]

If'n y'all believe my calcs, I'd like ta think the first guy to verify and cut/paste would be a lucky feller!

I think it's pretty damn rude, knowing that you don't qualify, to be posting guesses and expecting someone to plagiarize the work of a troll.

[dajones]

I think it's pretty damn rude, knowing that you don't qualify, to be posting guesses and expecting someone to plagiarize the work of a troll.

A... troll? I dinna say, e.g., "Obama is the greatest President evah!" Nor even "Don't you know cigars'll KILL YA?" You know... classic trolls.

As suggested by the OP: "Show your work." In other words, how, exactly, am I trolling?

Edit:

But, since the OP himself objects, I guess I'll move along.

(Oh: OP: I wazna tryin' to show how smaht *I* am, but how tuff it mus' be to pass the fireman's exam...)

Sorry to bust in on your party. Friendly site y'all got here...

[buzz]

t = ~7 seconds

*whew*

"Math is Hard"; "Let's go shopping!"

If'n y'all believe my calcs, I'd like ta think the first guy to verify and cut/paste would be a lucky feller!

Dude, seriously - what the hell are you thinking? This contest is meant to be a fun thing for the contributing members of this site. There are rules listed at the top for a reason. Your attempt to show how smart you are is not appreciated, nor is the disrespect that you have shown me and this forum.

Go away.

-Buzz

[ashauler]

....snip
Yet another forum (I hang at BOTL and Puff) where I hafta establish some sorta bona fides before being allowed to play.

Good luck guys!

Yeah, this place is very different than those two, thank goodness.

[dajones]

• The average size of the cigars is 5x50 cause you really dig those Robustos.
• The Heat Release Rate of 1 cubic foot of tequila-soaked cigars can be assumed to be 250 BTU/s.
• The inside temperature is 75 degrees F because your wife is always cold.
• The detector alarm temperature is 135 degrees F.
• The ceiling height in the living room is 10 ft and the ceiling is flat.
• The heat detector is located on the living room ceiling, approximately 2 ft. from the centerline of the fire.
• The Response Time Index (RTI) of the heat detector is 100.
• The fire can be assumed to be Steady State.

Hmmm

okay, we need something like /ceiling jet lag time (assume 1.2) = .833

we need radial distance to detector (stated as 2 feet)

we need height of ceiling (10 feet)

and heat release rate (given = 250 btus)

raise radius to 11/6 = 2^11/6 = 3.56

Now calc release rate^1.3 times height^1/2

BUT: convert BTU to KW (what, like... BTU/minute equals 0.01757 kilowatt so 250*60/0.01757 =~ 854,000kw/min)
I'll prolly hafta get back to heat release conversions...

T=1/(jet lag) * 3.56/10^(0.5)*Heat Release^(.333) = ~3/(3.2*Heat Release)

I kin already see Imma WRONG cuz this is gonna make a rilly smaaaallll #....

Back ta the drawing board

[badwhale]

50-4 = 46 post deficiet to compete in contest.

• The average size of the cigars is 5x50 cause you really dig those Robustos.
• The Heat Release Rate of 1 cubic foot of tequila-soaked cigars can be assumed to be 250 BTU/s.
• The inside temperature is 75 degrees F because your wife is always cold.
• The detector alarm temperature is 135 degrees F.
• The ceiling height in the living room is 10 ft and the ceiling is flat.
• The heat detector is located on the living room ceiling, approximately 2 ft. from the centerline of the fire.
• The Response Time Index (RTI) of the heat detector is 100.
• The fire can be assumed to be Steady State.

Hmmm

okay, we need something like /ceiling jet lag time (assume 1.2) = .833

we need radial distance to detector (stated as 2 feet)

we need height of ceiling (10 feet)

and heat release rate (given = 250 btus)

raise radius to 11/6 = 2^11/6 = 3.56

Now calc release rate^1.3 times height^1/2

BUT: convert BTU to KW (what, like... BTU/minute equals 0.01757 kilowatt so 250*60/0.01757 =~ 854,000kw/min)
I'll prolly hafta get back to heat release conversions...

T=1/(jet lag) * 3.56/10^(0.5)*Heat Release^(.333) = ~3/(3.2*Heat Release)

I kin already see Imma WRONG cuz this is gonna make a rilly smaaaallll #....

Back ta the drawing board