• The average size of the cigars is 5x50 cause you really dig those Robustos.
• The Heat Release Rate of 1 cubic foot of tequila-soaked cigars can be assumed to be 250 BTU/s.
• The inside temperature is 75 degrees F because your wife is always cold.
• The detector alarm temperature is 135 degrees F.
• The ceiling height in the living room is 10 ft and the ceiling is flat.
• The heat detector is located on the living room ceiling, approximately 2 ft. from the centerline of the fire.
• The Response Time Index (RTI) of the heat detector is 100.
• The fire can be assumed to be Steady State.

Hmmm

okay, we need something like /ceiling jet lag time (assume 1.2) = .833

we need radial distance to detector (stated as 2 feet)

we need height of ceiling (10 feet)

and heat release rate (given = 250 btus)

raise radius to 11/6 = 2^11/6 = 3.56

Now calc release rate^1.3 times height^1/2

BUT: convert BTU to KW (what, like... BTU/minute equals 0.01757 kilowatt so 250*60/0.01757 =~ 854,000kw/min)
I'll prolly hafta get back to heat release conversions...

T=1/(jet lag) * 3.56/10^(0.5)*Heat Release^(.333) = ~3/(3.2*Heat Release)

I kin already see Imma WRONG cuz this is gonna make a rilly smaaaallll #....

Back ta the drawing board